How do you find the numeric value of angle A and B for triangle ABC with C being the right angle given A=x and $B = x^{2}$ $B=x^2$ ?

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Answer 1 · 2016-10-14T12:58:34

Angle A measures $9˚$ while angle B measures $81˚$ .

The angles in any triangle always add up to $180˚$ .

So,

$x^2 + x + 90 = 180$

$x^2 + x - 90 = 0$

Solve by factoring.

$(x + 10)(x - 9) = 0$

$x = -10 and 9$

A negative answer isn't possible, so the angles measure $9˚$ and $9^2 = 81˚$ .

Hopefully this helps!

How do you find the numeric value of angle A and B for triangle ABC with C being the right angle given A=x and B=x^2B=x2B=x^2?