# How do you graph #r=4sin(5theta)#?

##### 1 Answer

Oct 21, 2017

Please see below.

#### Explanation:

graph{((x^2+y^2)^(3/2)-6xy)((x^2+y^2)^(3/2)+6xy)=0 [-10, 10, -5, 5]}

But

graph{(x^2+y^2)^3=20y(x^2+y^2)^2-80y^3(x^2+y^2)+64 y^5 [-10, 10, -5, 5]}

Observe that when