How do you graph the equation y=-3/7x+2?

Oct 17, 2017

See a solution process below:

Explanation:

This equation is in slope intercept form. The slope-intercept form of a linear equation is: $y = \textcolor{red}{m} x + \textcolor{b l u e}{b}$

Where $\textcolor{red}{m}$ is the slope and $\textcolor{b l u e}{b}$ is the y-intercept value.

$y = \textcolor{red}{- \frac{3}{7}} x + \textcolor{b l u e}{2}$

Therefore:

The $y$-intercept is: $\textcolor{b l u e}{2}$ or $\left(0 , \textcolor{b l u e}{2}\right)$

The slope is: $\textcolor{red}{m = - \frac{3}{7}}$

Slope is rise over run. So the line will go down $3$ units while it goes to the right $7$ units.

We can plot the $y$-intercept as:

graph{(x^2+(y-2)^2-0.025)=0}

We can plot the next point by going down $3$ units and to the right $7$ units which is at: $\left(7 , - 1\right)$

We can now draw a line through the two points to graph the line:

graph{(y + (3/7)x - 2)((x-7)^2+(y+1)^2-0.025)(x^2+(y-2)^2-0.025)=0}