# How do you graph using slope and intercept of 8x - 6y = -20?

Jul 4, 2018

See below:

#### Explanation:

When an equation is in slope-intercept form

$y = m x + b$, we know that $m$ is the slope and $b$ is the $y$-intercept.

In our example, we only want a $y$ on the left side, so we can start by subtracting $8 x$ from both sides to get

$- 6 y = - 8 x - 20$

Divide all terms by $- 6$ to get

$y = \frac{4}{3} x + \frac{10}{3}$

We can start at our $y$-intercept, and from that point, go up $4$ in the $y$-direction and right $3$ in the $x$-direction. We get the graph

graph{y=4/3x+10/3 [-10, 10, -5, 5]}

Hope this helps!