# How do you make a graph of the rosy limacon #r = 1 + 2 cos 3theta#?

##### 1 Answer

Nov 25, 2016

The graph is inserted after conversion that befits cartesian frame.

#### Explanation:

You can see that rose curves

limacons, with n = 1.

See the roses, with

a = 1 and b =2, giving

= 2, giving

graph{(x^2+y^2)^2-(x^2+y^2)^1.5-2x^3+6xy^2=0 [-10 10 -5 5]}

graph{(x^2+y^2)^3.5-(x^2+y^2)^3-2(x^6-y^6)+30x^2y^2(x^2-y^2)=0 [10 10 -5 5]}

graph{(x^2+y^2)^3.5-2(x^2+y^2)^3-(x^6-y^6)+15x^2y^2(x^2-y^2)=0 [10 10 -5 5]}