How do you sketch the graph #y=sinx+sin^2x# using the first and second derivatives from #0<=x<2pi#?
1 Answer
Jun 12, 2017
Please see below.
Explanation:
We have
Observe that
hence between
Now we have extrema when
also
Hence extrema occurs when
Hence we have a local minima at
The graph appears as shown below.
graph{sinx(1+sinx) [-2.917, 7.083, -1.84, 3.16]}