How do you solve $10n^2+2=292$ ?

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Answer 1 · 2017-03-17T18:43:37

$+-sqrt29$ or $+-5.38516481$

Subtract 2 from both sides.

$10n^2+cancel2-cancel2=cancel(292-2) 290$

Divide both sides by 10.

$(cancel10n^2)/cancel10=(cancel290 29)/cancel10$

Square root both sides.

$sqrt(n^2)=sqrt29$

$*$ Remember to include both the positive and negative square root answers.

$n=+-sqrt29$

$*$ If a decimal answer is needed, find it using a calculator.

$+-sqrt29=+-5.38516481$

How do you solve 10n^2+2=29210n^2+2=292?