How do you solve #10n^2+2=292#?

Question

2771 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-03-17T18:43:37

#+-sqrt29# or #+-5.38516481#

Subtract 2 from both sides.

#10n^2+cancel2-cancel2=cancel(292-2) 290#

Divide both sides by 10.

#(cancel10n^2)/cancel10=(cancel290 29)/cancel10#

Square root both sides.

#sqrt(n^2)=sqrt29#

#*#Remember to include both the positive and negative square root answers.

#n=+-sqrt29#

#*#If a decimal answer is needed, find it using a calculator.

#+-sqrt29=+-5.38516481#