# How do you solve 10p^2+2=12?

May 3, 2017

$p = 1 \mathmr{and} - 1$

#### Explanation:

$10 {p}^{2} + 2 = 12$

=$10 {p}^{2} = 10$

=${p}^{2} = 1$

$\pm \sqrt{p} =$ could be 1 or -1 since both ${1}^{2}$ and ${\left(- 1\right)}^{2}$ gives 1