How do you solve #13-8n^2=-1139#?

1 Answer
Mar 7, 2017

Answer:

See the entire solution process below:

Explanation:

First, subtract #color(red)(13)# from each side of the equation to isolate the #n# term while keeping the equation balanced:

#-color(red)(13) + 13 - 8n^2 = -color(red)(13) - 1139#

#0 - 8n^2 = -1152#

#-8n^2 = -1152#

Next, divide each side of the equation by #color(red)(-8)# to isolate #n^2# while keeping the equation balanced:

#(-8n^2)/color(red)(-8) = (-1152)/color(red)(-8)#

#(color(red)(cancel(color(black)(-8)))n^2)/cancel(color(red)(-8)) = 144#

#n^2 = 144#

Now, take the square root of each side of the equation to solve for #x# while keeping the equation balanced. Remember, the square root of a number produces both a positive and a negative result:

#sqrt(n^2) = +-sqrt(144)#

#n = +-12#