How do you solve #2(a-6)^2-45=53#?

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Answer 1 · 2016-08-18T20:34:50

#a =-1or a = 13#

This is a quadratic equation which we can solve by an easy method because there is no term in #a#.

#2(a-6)^2 -45=53" isolate the term with the variable"#

#2(a-6)^2 =53+45#

#2(a-6)^2 = 98" isolate the factor with the variable"#

#(a-6)^2 =49" find the square root of both sides"#

#a-6 = +-7#

#a-6 = +7 rArr a = 7+6 = 13#
#a-6 = -7 rArr a = -7+6 = -1#