How do you solve #(2k-1)^2=9#?

1 Answer
Aug 16, 2016

Answer:

#k= 2# or #k = -1#

Explanation:

you can take the square root from both sides but you must remember that there will be two possible options. Either the value will be positive or negative so
#2k-1 = 3# or #1-2k = 3#
#2k= 4# or #-2k = 2#
#k= 2# or #k = -1#

then we plug both in and see if they work
and they both indeed do.