# How do you solve 2m^2+10=210?

Jul 23, 2016

color(purple)("m = 10

#### Explanation:

color(magenta)("Subtract 10 on both sides of the equation:"
$2 {m}^{2} + \cancel{10} = 210$
$\textcolor{w h i t e}{a a a a} \cancel{-} 10 - 10$

On the left side you should be left with 2m^(2), and on the right side you are left with 200:

$2 {m}^{2} = 200$

Next, divide both sides both 2 in order to get the variable and constant on opposite sides of the equals sign. This will allow you to solve for $m$ in the next few steps:

$\frac{\cancel{2} {m}^{2}}{\cancel{2}} = \frac{200}{2}$

The 2's cancel out, leaving you with ${m}^{2}$ equal to 100

${m}^{2} = 100$

In order to get rid of ${m}^{2}$ to solve for just $m$, you will need to take the square root on both sides of the equation, since the square root is the inverse of a number that's squared:

${\sqrt{m}}^{2} = \sqrt{100}$

After you square both sides, you are left with $m$ on the left and 10 on the right.

Thus,
color(purple)("m = 10