How do you solve #3+36p^2=103#?

2 Answers
Feb 19, 2017

Answer:

Collect like terms and move the numbers until the equation reads #p^2=...# Then, take the square root of both sides of the equation.

Explanation:

Here it is:

#36p^2 = 103 -3# (we subtract 3 from each side)

#36p^2=100#

Next, divide each side by 36

#p^2=100/36#

(Resist the temptation to convert to decimals at this stage. It is actually easier with fractions!)

Square root:

#p=sqrt(100/36) = (sqrt100)/(sqrt36) = +-10/6 = +-5/3#

So, we have two answers (as expected!)

#5/3# and #-5/3#

Feb 19, 2017

Answer:

See the entire solution process below:

Explanation:

First, subtract #color(red)(3)# from each side of the equation to isolate the #p^2# term while keeping the equation balanced:

#-color(red)(3) + 3 + 36p^2 = -color(red)(3) + 103#

#0 + 36p^2 = 100#

#36p^2 = 100#

Next, divide each side of the equation by #color(red)(36)# to isolate #p^2# while keeping the equation balanced:

#(36p^2)/color(red)(36) = 100/color(red)(36)#

#p^2 = 100/36#

Now, take the square root of each side of the equation to solve for #p# while keeping the equation balanced. Remember, when taking the square root of a number there is a negative and positive result:

#sqrt(p^2) = +-sqrt(100/36)#

#p = +-sqrt(100)/sqrt(36)#

#p = +-10/6#

#p = +-5/3#