# How do you solve 3m^2+7=301?

Sep 20, 2016

$m = \pm 7 \sqrt{2}$

#### Explanation:

$3 {m}^{2} + 7 = 301$

$3 {m}^{2} = 301 - 7 = 294$

${m}^{2} = \frac{294}{3} = 98$

$m = \pm \sqrt{98}$

When finding roots of intergers it is often useful for express the number as the product of its prime numbers.

$m = \pm \sqrt{2 \times 7 \times 7}$

Hence $m = \pm 7 \sqrt{2}$