How do you solve #3x^2+10=118#?

1 Answer
Sep 26, 2016

Answer:

#x = +-6#

Explanation:

While this is a quadratic and we would usually make it equal to 0, this is a special case in that there is no term in x.
Move the constants to the right side.

#3x^2 = 118-10#

#3x^2 = 108" "larrdiv# by 3

#x^2 = 36" "larr# find square root of both sides

#x = +-sqrt36#

#x = +-6#