How do you solve 3x^2+10=118?

Sep 26, 2016

$x = \pm 6$

Explanation:

While this is a quadratic and we would usually make it equal to 0, this is a special case in that there is no term in x.
Move the constants to the right side.

$3 {x}^{2} = 118 - 10$

$3 {x}^{2} = 108 \text{ } \leftarrow \div$ by 3

${x}^{2} = 36 \text{ } \leftarrow$ find square root of both sides

$x = \pm \sqrt{36}$

$x = \pm 6$