Question

How do you solve `3x^2+10=118`?

Answer 1

`x = +-6`

Explanation:

While this is a quadratic and we would usually make it equal to 0, this is a special case in that there is no term in x.
Move the constants to the right side.

`3x^2 = 118-10`

`3x^2 = 108" "larrdiv` by 3

`x^2 = 36" "larr` find square root of both sides

`x = +-sqrt36`

`x = +-6`