# How do you solve 4x^2+7=23?

Apr 25, 2018

see below...

#### Explanation:

First get the variable on one side and the constant on the other...
Subtract 7 from both sides.

$4 {x}^{2} = 16$

Now find ${x}^{2}$ so divide by 4 on both sides.

${x}^{2} = 4$

Now sqrt both sides. Remember square rooting gives us a $\pm$ answer.

$x = \pm 2$