How do you solve #5(x+3/4)^2-2=43#?

1 Answer
Feb 7, 2017

Answer:

#x=-15/4" or "x=9/4#

Explanation:

#"Isolate " (x+3/4)^2# on the left side of the equation.

add 2 to both sides.

#5(x+3/4)^2cancel(-2)cancel(+2)=43+2#

#rArr5(x+3/4)^2=45#

divide both sides by 5

#(cancel(5))/cancel(5)(x+3/4)^2=45/5#

#rArr(x+3/4)^2=9#

Take the #color(blue)"square root "# of both sides.

#sqrt((x+3/4)^2)=+-sqrt9#

#rArrx+3/4=+-3larrcolor(red)" 2 solutions"#

#color(blue)"Solution 1"#

#x=-3-3/4rArrx=-15/4#

#color(blue)"Solution 2"#

#x=+3-3/4=9/4#