# How do you solve 8(x+4)^2=9?

Jul 23, 2016

$x = - 2.939 \text{ or } x = - 5.061$

#### Explanation:

Do not be tempted to multiply it all out and make equal to 0.

$8 {\left(x + 4\right)}^{2} = 9 \text{ divide by 8}$

${\left(x + 4\right)}^{2} = \frac{9}{8} \text{ square root both sides}$t8#

$x + 4 = \pm \sqrt{\frac{9}{8}}$

$x = + \frac{3}{\sqrt{8}} - 4 \text{ or } x = - \frac{3}{\sqrt{8}} - 4$

$x = - 2.939 \text{ or } x = - 5.061$