# How do you solve 8v^2-12=308?

Oct 16, 2016

$v = \pm \sqrt{40}$

#### Explanation:

Usually a quadratic equation is solved by making it equal to 0.

However, this is a special case because there is no $x$-term.
We can solve it by finding the square root.

$8 {v}^{2} - 12 = 308$

$8 {v}^{2} = 320 \text{ } \leftarrow$ add 12 to both sides

${v}^{2} = 40 \text{ } \leftarrow \div 8$ on both sides

$v = \pm \sqrt{40}$