How do you solve #8v^2-12=308#?

1 Answer
Oct 16, 2016

Answer:

#v = +-sqrt40#

Explanation:

Usually a quadratic equation is solved by making it equal to 0.

However, this is a special case because there is no #x#-term.
We can solve it by finding the square root.

#8v^2 -12 = 308#

#8v^2 = 320" "larr# add 12 to both sides

#v^2 = 40" "larr div 8 # on both sides

#v = +-sqrt40#