# How do you solve x^2-6x+9=5 using square root property?

Feb 5, 2015

You need to factor ${x}^{2} - 6 x + 9$

This will give you:

$\left(x - 3\right) \left(x - 3\right) = 5$

Which of course is

${\left(x - 3\right)}^{2} = 5$

Now take the square of both sides:

$\sqrt{{\left(x - 3\right)}^{2}} = \pm \sqrt{5}$

$\left(x - 3\right) = \pm \sqrt{5}$

Now solve for x

$x = 3 \pm \sqrt{5}$