How do you solve $k^{2} + 6 = 6$ $k^2+6=6$ ?

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Answer 1 · 2016-09-27T16:31:47

$k = 0$ $color(green)(k=0)$

Given $k^{2} + 6 = 6$ $k^2+6=6$

After subtracting $6$ $6$ from both sides: $k^{2} = 0$ $k^2=0$

Taking the square root of both sides: $k = \pm \sqrt{0} = 0$ $k = +-sqrt(0) =0$

How do you solve k^2+6=6k2+6=6k^2+6=6?