How do you solve m^2+7=6?

Jan 28, 2017

$m = \pm i$

Explanation:

${m}^{2} + 7 = 6$ $\text{Subtract 6 from both sides}$

${m}^{2} + 7 - 6 = 6 - 6$, i.e. ${m}^{2} + 1 = 0$

So, ${m}^{2} + 1 = 0$

${m}^{2} = - 1$

$m = \pm \sqrt{- 1} = \pm i$

We see clearly that this has roots at $m = \pm i$. Do you agree?