# How do you solve n^2+4=40?

Aug 30, 2016

$n = + 6 \mathmr{and} n = - 6$

#### Explanation:

Although this is a quadratic equation, it is a special case because it does not have a term in $x$.

There are 2 methods:

${n}^{2} = 36$
$n = \pm \sqrt{36}$

$n = + 6 \mathmr{and} n = - 6$

Or we can do the usual method of making it equal to 0 and finding factors:

${n}^{2} - 36 = 0$

$\left(n + 6\right) \left(n - 6\right) = 0$

$n = - 6 \mathmr{and} n = + 6$