# How do you solve #n^2-5=-4#?

##### 2 Answers

Sep 1, 2016

#### Explanation:

To solve a quadratic equation we require to equate it to zero.

The first step is therefore to add 4 to both sides of the equation.

#rArrn^2-5+4=cancel(-4)+cancel(4)=0#

#rArrn^2-1=0" is the equation to be solved"# Now

#n^2-1 # is a#color(blue)"difference of squares"#

#rArr(n-1)(n+1)=0# solve:

#n-1=0rArrn=1# solve

#n+1=0rArrn=-1# Thus the solutions to the equation are

#n=+-1#

Sep 4, 2016

#### Explanation:

Although this is a quadratic equation, it is a special case because there is no 'n' term.

Isolate the