How do you solve #n^2+8=80#?

1 Answer
Feb 13, 2017

Answer:

#n=+-6sqrt2#

Explanation:

#"Isolate "n^2"# by subtracting 8 from both sides of the equation.

#n^2cancel(+8)cancel(-8)=80-8#

#rArrn^2=72#

Take the #color(blue)"square root"# of both sides.

#sqrt(n^2)=+-sqrt72#

#rArrn=+-sqrt72#

Simplifying #sqrt72#

#n=+-(sqrt(36xx2))#

#color(white)(n)=+-(sqrt36xxsqrt2)#

#rArrn=+-6sqrt2#