# How do you solve n^2+8=80?

Feb 13, 2017

$n = \pm 6 \sqrt{2}$

#### Explanation:

$\text{Isolate "n^2}$ by subtracting 8 from both sides of the equation.

${n}^{2} \cancel{+ 8} \cancel{- 8} = 80 - 8$

$\Rightarrow {n}^{2} = 72$

Take the $\textcolor{b l u e}{\text{square root}}$ of both sides.

$\sqrt{{n}^{2}} = \pm \sqrt{72}$

$\Rightarrow n = \pm \sqrt{72}$

Simplifying $\sqrt{72}$

$n = \pm \left(\sqrt{36 \times 2}\right)$

$\textcolor{w h i t e}{n} = \pm \left(\sqrt{36} \times \sqrt{2}\right)$

$\Rightarrow n = \pm 6 \sqrt{2}$