How do you solve #(p-4)^2=16#?
2 Answers
Aug 31, 2016
Explanation:
Although this is a quadratic, it is a special case in that there is no term in
We can simply find the square root of each side,
Aug 31, 2016
P=0 or 8
Explanation:
Take square root of both sides
So p-4=-4 which gives p=0
Or
p-4=4 which gives p=8