# How do you solve sqrt(-8-2a)=0?

Mar 6, 2017

See the entire solution process below:

#### Explanation:

First, square the expression on each side of the equation:

${\left(\sqrt{- 8 - 2 a}\right)}^{2} = {0}^{2}$

$- 8 - 2 a = 0$

Next, add $\textcolor{red}{8}$ to each side of the equation to isolate the $a$ term while keeping the equation balanced:

$\textcolor{red}{8} - 8 - 2 a = \textcolor{red}{8} + 0$

$0 - 2 a = 8$

$- 2 a = 8$

Now, divide each side of the equation by $\textcolor{red}{- 2}$ to solve for $a$ while keeping the equation balanced:

$\frac{- 2 a}{\textcolor{red}{- 2}} = \frac{8}{\textcolor{red}{- 2}}$

$\frac{\textcolor{red}{\cancel{\textcolor{b l a c k}{- 2}}} a}{\cancel{\textcolor{red}{- 2}}} = - 4$

$a = - 4$