Question

How do you solve the equation `1/7x^2-3=4`?

Answer 1

`x=+-7`

Explanation:

Start by adding 3 to both sides of the equation.

`1/7x^2cancel(-3)cancel(+3)=4+3`

`rArr1/7x^2=7`

multiply both sides by 7 to eliminate the fraction.

`cancel(7)^1xx1/cancel(7)^1 x^2=7xx7`

`rArrx^2=49`

Take the `color(blue)"square root of both sides"`

`sqrt(x^2)=+-sqrt49`

`rArrx=+-7larrcolor(red)" are the solutions"`