How do you solve the equation #1/7x^2-3=4#?

1 Answer
Apr 3, 2017

Answer:

#x=+-7#

Explanation:

Start by adding 3 to both sides of the equation.

#1/7x^2cancel(-3)cancel(+3)=4+3#

#rArr1/7x^2=7#

multiply both sides by 7 to eliminate the fraction.

#cancel(7)^1xx1/cancel(7)^1 x^2=7xx7#

#rArrx^2=49#

Take the #color(blue)"square root of both sides"#

#sqrt(x^2)=+-sqrt49#

#rArrx=+-7larrcolor(red)" are the solutions"#