# How do you solve the equation 4(x+5)^2=-64?

Jun 20, 2017

$x = - 5 \pm 4 i$

#### Explanation:

$\text{Isolate " (x+5)^2" by dividing both sides by 4}$

$\Rightarrow {\left(x + 5\right)}^{2} = - 16$

${\left(x + 5\right)}^{2} \ge 0 \text{ hence there are no real roots}$

$x + 5 = \pm \sqrt{- 16}$

$\textcolor{w h i t e}{x + 5} = \pm 4 i$

$\Rightarrow x = - 5 \pm 4 i$