# How do you solve the equation ax^2+5=3?

May 18, 2018

In terns of x:

$x = \pm \sqrt{\frac{- 2}{a}}$

if a is not negative the solution will be imaginary.

#### Explanation:

$a {x}^{2} + 5 = 3$

$a {x}^{2} + 5 - 5 = 3 - 5$

$a {x}^{2} = - 2$

$\frac{a {x}^{2}}{a} = \frac{- 2}{a}$

${x}^{2} = \frac{- 2}{a}$

$\sqrt{{x}^{2}} = \pm \sqrt{- \frac{2}{a}}$

$x = \pm \sqrt{\frac{- 2}{a}}$