How do you solve the equation #x^2+169=0#?

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Answer 1 · 2017-04-16T00:06:05

NO REAL SOLUTIONS but rather complex solutions:

#x = -13i, 13i#

Isolate the #x^2# by subtracting 169 from both sides...

#x^2+cancel(169-169)=0-169 -> x^2 = -169#

Now take the square root of both sides to the #x#

#sqrt(x^2)= sqrt(-169) -> x= +- sqrt(-169)#

Note: there are NO REAL SOLUTIONS! but rather two complex solutions denoted by the symbol #i#

So #x = -13i, 13i#