How do you solve the triangle given A=110°, a=125, b=100?

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Answer 1 · 2018-03-27T09:05:58

$color(blue)(Delta " " A_t = (1/2) a b sin C = 2316 " sq units"$

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$a = 125, b = 100, hat A = 110^@$

$sin B = (b * sin A) / a = (100 * sin 110) / 125 = 0.7518$

$hat B = sin ^ -1 0.7518 = 48.75^@$

$hat C = 180 - 110 - 48.75 = 21.25^@$

$Delta " " A_t = (1/2) a b sin C = (1/2) * 125 * 100 * sin 21.25 = 2316$