# How do you solve using the square root method 2x^2-5=93?

May 5, 2016

There is no $x$ term, so we can just find the square root.
Remember that a number has a positive root and a negative root.

#### Explanation:

$2 {x}^{2} - 5 = 93$

$\textcolor{w h i t e}{\times x}$$2 {x}^{2}$ = $93 + 5$

$\textcolor{w h i t e}{\times x}$$2 {x}^{2} = 98$ $\textcolor{w h i t e}{\times \times \times \times x}$ divide by 2.

$\textcolor{w h i t e}{\times x}$${x}^{2} = 49$

$x = \pm \sqrt{49}$
$x = \pm 7$