# How do you solve x^2-5=73?

Feb 17, 2017

See the entire solution process below:

#### Explanation:

Because this equation has no $x$ term we can solve directly for ${x}^{2}$. First, add $\textcolor{red}{5}$ to each side of the equation to isolate the ${x}^{2}$ ter while keeping the equation balanced:

${x}^{2} - 5 + \textcolor{red}{5} = 73 + \textcolor{red}{5}$

${x}^{2} - 0 = 78$

${x}^{2} = 78$

Now, take the square root of each side of the equation to solve for $x$ while keeping the equation balanced. Also remember, the square root of a number will have both a negative and positive answer:

$\sqrt{{x}^{2}} = \pm \sqrt{78}$

$x = \pm \sqrt{78} = \pm 8.832$ rounded to the nearest thousandth.