How do you solve #x^2/6-2=0#?

1 Answer
Feb 15, 2017

Answer:

See the entire solution process below:

Explanation:

First, add #color(red)(2)# to each side of the equation to isolate the #x^2# term while keeping the equation balanced:

#x^2/6 - 2 + color(red)(2) = 0 + color(red)(2)#

#x^2/6 - 0 = 2#

#x^2/6 = 2#

Next, multiply each side of the equation by #color(red)(6)# to isolate #x^2# while keeping the equation balanced:

#color(red)(6) xx x^2/6 = color(red)(6) xx 2#

#cancel(color(red)(6)) xx x^2/color(red)(cancel(color(black)(6))) = 12#

#x^2 = 12#

Now, take the square root of each side of the equation to solve for #x# while keeping the equation balanced. Remember, taking the square root of a number results in a positive and negative solution.

#sqrt(x^2) = +-sqrt(12)#

#x = +-sqrt(12) = +-3.464# rounded to the nearest thousandth.