How do you solve #x^2+7x+10>0# using a sign chart?

1 Answer
Shwetank Mauria
Oct 1, 2016

#x<-5# or #x>-2#

Explanation:

Just see https://socratic.org/questions/how-do-you-solve-x-3-7x-2-10x-0

and try on similar lines

we have

Sign Chart

#color(white)(XXXXXXXXXXX)-5color(white)(XXXXX)-2#

#(x+5)color(white)(XXXX)-ive color(white)(XXXX)+ive color(white)(XX)+ive#

#(x+2)color(white)(XXXX)-ive color(white)(XXXX)-ive color(white)(XX)+ive#

#(x+5)(x+2)#
#color(white)(XXXXXXXX)+ive color(white)(XXXX)-ive color(white)(XX)+ive#

#x^2+7x+10>0# when #x<-5# or #x > -2#

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