# How do you solve (x + 3)^2 - 3 = 13?

${\left(x + 3\right)}^{2} - 3 = 13 \Rightarrow {\left(x - 3\right)}^{2} = 16 \Rightarrow x + 3 = \pm 4 \Rightarrow$
$x = - 3 \pm 4$
${x}_{1} = - 3 - 4 = - 7$;
${x}_{2} = - 3 + 4 = 1$.