# How do you write 9x=2y+13 in slope intercept form?

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Meave60 Share
Oct 1, 2016

$y = \frac{9}{2} x - \frac{13}{2}$

#### Explanation:

The slope-intercept form for a linear equation is $y = m x + b$, where $m$ is the slope and $b$ is the y-intercept.

In order to write the equation $9 x = 2 y + 13$ in slope-intercept form, solve for $y$.

$9 x = 2 y + 13$

Subtract $2 y$ from both sides.

$- 2 y + 9 x = 13$

Subtract $9 x$ from both sides.

$- 2 y = - 9 x + 13$

Divide both sides by $- 2$.

$y = \frac{- 9 x}{- 2} + \frac{13}{- 2}$

Simplify.

$y = \frac{9}{2} x - \frac{13}{2}$

$m = \frac{9}{2}$
$b = - \frac{13}{2}$

graph{y=9/2x-13/2 [-10.85, 9.15, -8.19, 1.81]}

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Noah G Share
Oct 1, 2016

Slope intercept form is $y = m x + b$.

$9 x - 13 = 2 y$

$y = \frac{9}{2} x - \frac{13}{2}$

Hopefully this helps!

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