# How do you write the equation y-1=-2(x-5) in slope intercept form?

Jul 29, 2017

Distribute the $- 2$ to the $x$ and $- 5$, add $1$ to both sides of the equation.

#### Explanation:

Remember, slope-intercept form is represented as y=mx+b

Start on the right side of the equation, and distribute the $- 2$.
$- 2$ times $x = - 2 x$ and $- 2 \left(- 5\right) = 10$.

Now we have the equation $y - 1 = - 2 x + 10$. The only thing left to do is add $1$ to both sides of the equation so that the variable y is the only thing on the left side of the equation.

On the left hand side, the $- 1$ and $+ 1$ will cancel each other out, leaving the variable $y$. On the right hand side, add $1$ to the $10$ only, to get $11$**.

$y = - 2 x + 11$

We have obtained an equation in slope intercept form (y=mx+b), where $m = - 2 \mathmr{and} b = 11$.