How many real roots are in y=2x^2-7x-15?

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Answer 1 · 2018-03-29T06:14:25

The real roots in #y=2x^2-7x-15# are #x=-3/2# and #x=5#.

#y=2x^2-7x-15#

#y=0#

#2x^2-7x-15=0#

Attempting to factorise

#2x^2+3x-10x-15=0#

#x(2x+3)-5(2x+3)=0#

#(x-5)(2x+3)=0#

#x-5=0#

#x=5#

#2x+3=0#

#2x=-3#

#x=-3/2#

The real roots in #y=2x^2-7x-15# are #x=-3/2# and #x=5#.