If x^2=4(5-1) what is the value of x?

Nov 28, 2016

This equation has 2 solutions: $x = - 4 \vee x = 4$

Explanation:

${x}^{2} = 4 \left(5 - 1\right)$ First we have to multiply the right side.

${x}^{2} = 4 \cdot 4$

${x}^{2} = 16$ Now we can take a square root of both sides remembering that $\sqrt{{x}^{2}} = | x |$

$| x | = 4$

$x = - 4 \vee x = 4$