Dear friends, Please read our latest blog post for an important announcement about the website. ❤, The Socratic Team

Is there a way to plot just one point on the graph feature?

I have been unable to figure out if this is an actual option, or if I will have to use another graph generator. I've avoided answering a lot of questions when they need just a couple points plotted. Thanks!

I have been unable to figure out if this is an actual option, or if I will have to use another graph generator. I've avoided answering a lot of questions when they need just a couple points plotted. Thanks!

1 Answer
Write your answer here...
Start with a one sentence answer
Then teach the underlying concepts
Don't copy without citing sources
preview
?

Answer

Write a one sentence answer...

Answer:

Explanation

Explain in detail...

Explanation:

I want someone to double check my answer

Describe your changes (optional) 200

1
Mar 22, 2018

Answer:

Sure can

Explanation:

A common question that gets asked is to plot a couple of points and then to connect them with a line. For this example, let's use #(0,0) and (3,3)#

In the grapher, you can graph small circles around the points in question and the line by using the format (note that the graph isn't operating in this example because of the space between graph and the bracket):

graph {(function 1)(function 2)(...)=0}

The graph of a line is #(x-x_1)^2+(y-y_1)^2-.1# (the .1 is the size of the circle - make the number bigger for bigger circles)

And so we can graph the two points and the line this way:

graph {((x-0)^2+(y-0)^2-.1)((x-3)^2+(y-3)^2-.1)(y-x)=0}

and it ends up looking like this:

graph{((x-0)^2+(y-0)^2-.1)((x-3)^2+(y-3)^2-.1)(y-x)=0}

There are several great answers on this topic. Here are a couple:

https://socratic.org/questions/useful-to-plot-points-on-socratic-graph

https://socratic.org/questions/how-can-i-access-graph-package-for-illustrating-solutions-to-questions

Was this helpful? Let the contributor know!
1500
Impact of this question
29 views around the world
You can reuse this answer
Creative Commons License