# Please help How do you graph the polar equation r=8-sec#theta# ?

##### 1 Answer

See the explanation and graphs.

#### Explanation:

As sec values

r is periodic,with period

Short Table, for $theta in

The graph is symmetrical about

graph is outside the annular ( circular ) region # 7 < r < 9 ).

Converting to the Cartesian form, using

The Socratic graph is immediate, with asymptote x = 0.

graph{((x^2 + y^2)^0.5(1+1/x) - 8)(x+0.01y)=0[-40 40 -20 20]}

See the bounding circles

graph{((x^2 + y^2)^0.5(1+1/x) - 8)(x^2+y^2-49)(x^2+y^2-81)=0[-20 20 -10 10]}