What is the limit as x approaches 0 of #5x^4+8x^2#?

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Answer 1 · 2018-03-26T22:08:19

The limit is #0#.

Simply plug in zero for #x#:

#color(white)=lim_(xrarr0) 5x^4+8x^2#

#=5(0)^4+8(0)^2#

#=5*0+8*0#

#=0+0#

#=0#

You can take a look at the graph of the function and verify this:

graph{5x^4+8x^2 [-1, 1, -1.1, 1.1]}