# What is the type of curve represented by the equation #r=sin6theta#?

##### 1 Answer

#### Explanation:

graph{(x^2+y^2)^3.5-6xy(x^4+y^4)+20x^3y^3=0 [-2 2 -1 1]}

The period =

There is just one loop:

For this loop,

For conversion, I have used

Likewise, in the same Cartesian frame, the graph is created for the

seldom cared yet grand

The shape is on uniform scale. The intruded arc over the zenith is

not a part of the graph, for one period. Please ignore it. Sans this

arc, the graph is OK.

graph{y-(x^2+y^2)(1-x^2-y^2)^0.5(6-32(x^2+y^2)(1-x^2-y^2))=0[-3 3 -1.5 1.5]}