Question

Where is the center of the graph of `(x+3)^2+(y-2)^2=4`?

Answer 1

Standard form:

`(x-h)^2+(y-k)^2=r^2`

where `(h,k)` is the center of the circle and `r` is the radius of the circle

The center of the circle is `(-3,2)`. You need to use the opposite signs for the numbers used in place of `(h,k)`