How do you solve #4x^2=52# solve using the square root property?

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Answer 1 · 2015-02-08T03:53:27

Using the square root property to solve this problem involves the following steps.

Isolate the squared term. (Already isolated.)

#4x^2 = 52#

Take the square of both sides, indicating that the solution can be positive or negative.

#sqrt(4x^2) = +-sqrt(52)#

Solve for x.

#2x = +-sqrt(4·13)#

#2x = +-sqrt(4)·sqrt(13)#

#2x = +-2 sqrt(13)#

#x = +-sqrt(13)#