How do you solve x^2+5x=-2x2+5x=−2 using the quadratic formula?

2 Answers
Nghi N.
Jul 10, 2015

Solve y = x^2 + 5x + 2 = 0y=x2+5x+2=0

Explanation:

D = d^2 = b^2 - 4ac = 25 - 8 = 16 = 4^2 -> d = +- 4D=d2=b2−4ac=25−8=16=42→d=±4

x = -b/(2a) +- d/(2a) = - 5/2 +- 4/2x=−b2a±d2a=−52±42

Meave60
Jul 10, 2015

x=(-5+sqrt(17))/2,x=−5+√172,(-5-sqrt(17))/2−5−√172

Explanation:

x^2+5x=-2x2+5x=−2

Quadratic Equation
Add 22 to both sides of the equation in order to make it fit the form of a quadratic equation: ax^2+bx+c=0ax2+bx+c=0.

x^2+5x+2=0x2+5x+2=0

a=1;a=1; b=5;b=5; c=2c=2

Quadratic Formula

x=(-b+-sqrt(b^2-4ac))/(2a)x=−b±√b2−4ac2a

x=(-5+-sqrt(5^2-4*1*2))/(2*1)x=−5±√52−4⋅1⋅22⋅1

x=(-5+-sqrt(25-8))/2x=−5±√25−82 =

x=(-5+-sqrt(17))/2x=−5±√172

x=(-5+sqrt(17))/2x=−5+√172

x=(-5-sqrt(17))/2x=−5−√172

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