How do you solve $2 k^{2} - 2 = 144$ $2k^2-2=144$ ?

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How do you solve $2 k^{2} - 2 = 144$ $2k^2-2=144$ ?

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Answer 1 · 2016-08-03T08:50:35

$k = \pm \sqrt{73}$ $k = +-sqrt73$

Explanation:

Notice that all the numbers are even. The first thing to do is to divide by 2.

$k^{2} - 1 = 72$ $k^2-1=72$

Usually in a quadratic equation, we make it equal to 0, but this is an exception because there is no $x -$ $x-$ term. Change it to $x^{2} = c$ $x^2 = c$

$k^{2} = 73$ $k^2 = 73$

$k = \pm \sqrt{73}$ $k = +-sqrt73$ Remember to take the positive and negative root.

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How do you solve $2 k^{2} - 2 = 144$ $2k^2-2=144$ ?

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Explanation:

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How do you solve $2 k^{2} - 2 = 144$ $2k^2-2=144$ ?