Question

What value of `b` makes the polynomial `x^2+ bx+16` a perfect square?

Answer 1

`b=+-8`

Explanation:

`x^2+bx+16` to become perfect square
`b^2-4ac=0` where `a=1 and c=16`
Therefore
`b^2=4ac`
or
`b^2=4(16)`
or
`b^2=64`
or
`b=+-sqrt64`
or
`b=+-8`